How Many Amps Is 0.85 kW at 24V?

0.85 kilowatts at 24V works out to roughly 35.42 amps on DC at PF 0.85. That is typical for solar arrays, battery banks, and DC industrial equipment. See the DC and alternate-phase numbers below for other circuit types.

0.85 kW at 24V, DC (PF 0.85)
35.42 Amps
0.85 kilowatts at 24V on DC ≈ 35.42 amps
AC Single Phase (PF 0.85)41.67 A
35.42

Formulas

DC: kW to Amps

I(A) = 1000 × P(kW) ÷ V(V)

1000 × 0.85 ÷ 24 = 850 ÷ 24 = 35.42 A

AC Single Phase (PF = 0.85)

I(A) = 1000 × P(kW) ÷ (PF × V(V))

850 ÷ (0.85 × 24) = 850 ÷ 20.4 = 41.67 A

Equipment & Circuit Sizing

Breaker Sizing

Breaker ratings are in amps, not watts, so the real install answer depends on the equipment nameplate FLA, whether the load is continuous (NEC 210.19(A) sizes the conductor and OCP at 125% of a continuous load, equivalently 80% of breaker rating), conductor ampacity and temperature rating, ambient and bundling derates, and any motor or HVAC provisions (NEC 430 / 440). At roughly 35.42A on DC at 24V, the load sits in the bracket between a 40A standard size (non-continuous) and the next size up that covers a continuous load under 210.19(A) (around 45A). The actual install pick depends on whether the load is continuous and the factors above; a conversion page can't pick a single "right" breaker from the amp draw alone.

Energy Cost

0.85 kW costs $0.14/hour at $0.17/kWh (rates last reviewed April 2026). See breakdown.

Power Factor Reference (DC)

How the line current for 0.85 kW at 24V changes with load power factor, on the same DC circuit basis the rest of the page uses. DC has no power factor; PF 1.0 represents resistive AC loads.

Load TypePF0.85 kW at 24V (DC)
Resistive (heaters, incandescent)135.42 A
Fluorescent lamps0.9535.42 A
LED lighting0.935.42 A
Synchronous motors0.935.42 A
Typical mixed loads0.8535.42 A
Induction motors (full load)0.835.42 A
Computers (without PFC)0.6535.42 A
Induction motors (no load)0.3535.42 A

AC Conversion Comparison

On DC, 0.85kW at 24V draws 35.42A. AC single-phase at PF 0.85 pulls 41.67A because reactive current is added on top of the real power.

Circuit TypeFormulaResult
DC850 ÷ 2435.42 A
AC Single Phase (PF 0.85)850 ÷ (0.85 × 24)41.67 A

Other kW Values at 24V

kWDC AmpsAC 1-Phase PF 0.85
0.5 kW20.83 A24.51 A
0.75 kW31.25 A36.76 A
1 kW41.67 A49.02 A
1.5 kW62.5 A73.53 A
2 kW83.33 A98.04 A
2.5 kW104.17 A122.55 A
3 kW125 A147.06 A
3.5 kW145.83 A171.57 A
4 kW166.67 A196.08 A
5 kW208.33 A245.1 A
6 kW250 A294.12 A
7.5 kW312.5 A367.65 A
8 kW333.33 A392.16 A
10 kW416.67 A490.2 A
12 kW500 A588.24 A

Frequently Asked Questions

0.85 kW at 24V draws about 35.42 amps on DC. Alternate cases at the same voltage: 41.67A on AC single-phase.
0.85 kW can be either. Residential loads up to about 5 kW (water heaters, dryers, EV chargers at 240V) are usually single-phase; commercial panels often serve the same load three-phase at 208V or 480V.
On AC single-phase, current scales inversely with power factor. At PF 1.0 (pure resistive, like a heater), 0.85 kW at 24V draws 35.42A. At PF 0.80 (typical induction motor), the same real power draws 44.27A. The extra current is reactive and does no real work, but still flows through the wire and the breaker.
At 24V, this is Level 1 territory (120V AC, single-phase, typically 12-16A). A 0.85 kW draw on a standard 120V household outlet is at or above the 1,440W NEC 210.19(A) continuous figure, which is why Level 1 EVSE ships at 1.4-1.9 kW and takes 20+ hours for a full charge. If you need 0.85 kW of charging, you want Level 2 on a 240V dedicated circuit, not 120V.
DC: Amps = (kW × 1000) ÷ Volts. AC single-phase: Amps = (kW × 1000) ÷ (Volts × PF). AC three-phase: Amps = (kW × 1000) ÷ (VoltsL-L × √3 × PF).
This calculator provides estimates for reference purposes only. Always consult a licensed electrician and verify compliance with the National Electrical Code (NEC) and local electrical codes before performing any electrical work.