How Many Amps Is 1.35 kW at 575V?

1.35 kW at 575V draws about 1.6 amps on an AC three-phase circuit at PF 0.85, typical for commercial HVAC, industrial motors, rooftop units, and three-phase panel loads. Actual current varies with equipment power factor and duty cycle.

1.35 kW at 575V, AC three-phase (PF 0.85)
1.6 Amps
1.35 kilowatts at 575V on AC three-phase ≈ 1.6 amps
AC Single Phase (PF 0.85)2.77 A
DC (ideal baseline)2.35 A
1.6

Formulas

DC: kW to Amps

I(A) = 1000 × P(kW) ÷ V(V)

1000 × 1.35 ÷ 575 = 1,354 ÷ 575 = 2.35 A

AC Single Phase (PF = 0.85)

I(A) = 1000 × P(kW) ÷ (PF × V(V))

1,354 ÷ (0.85 × 575) = 1,354 ÷ 488.75 = 2.77 A

AC Three Phase (PF = 0.85)

I(A) = 1000 × P(kW) ÷ (√3 × PF × VL-L), where VL-L is the line-to-line voltage

1,354 ÷ (1.732 × 0.85 × 575) = 1,354 ÷ 846.52 = 1.6 A

Equipment & Circuit Sizing

Breaker Sizing

Breaker ratings are in amps, not watts, so the real install answer depends on the equipment nameplate FLA, whether the load is continuous (NEC 210.19(A) sizes the conductor and OCP at 125% of a continuous load, equivalently 80% of breaker rating), conductor ampacity and temperature rating, ambient and bundling derates, and any motor or HVAC provisions (NEC 430 / 440). At roughly 1.6A on AC three-phase at 575V, the load sits in the bracket between a 15A standard size (non-continuous) and the next size up that covers a continuous load under 210.19(A). The actual install pick depends on whether the load is continuous and the factors above; a conversion page can't pick a single "right" breaker from the amp draw alone.

Energy Cost

1.35 kW costs $0.23/hour at $0.17/kWh (rates last reviewed April 2026). See breakdown.

Power Factor Reference (AC three-phase)

How the line current for 1.35 kW at 575V changes with load power factor, on the same AC three-phase circuit basis the rest of the page uses. DC has no power factor; PF 1.0 represents resistive AC loads.

Load TypePF1.35 kW at 575V (AC three-phase)
Resistive (heaters, incandescent)11.36 A
Fluorescent lamps0.951.43 A
LED lighting0.91.51 A
Synchronous motors0.91.51 A
Typical mixed loads0.851.6 A
Induction motors (full load)0.81.7 A
Computers (without PFC)0.652.09 A
Induction motors (no load)0.353.88 A

AC Conversion Comparison

On DC, 1.35kW at 575V draws 2.35A. AC single-phase at PF 0.85 pulls 2.77A because reactive current is added on top of the real power. Three-phase at the same voltage needs only 1.6A per line since the same 1.35kW is shared across three conductors instead of one.

Circuit TypeFormulaResult
DC1,354 ÷ 5752.35 A
AC Single Phase (PF 0.85)1,354 ÷ (0.85 × 575)2.77 A
AC Three Phase (PF 0.85)1,354 ÷ (1.732 × 0.85 × 575)1.6 A

Other kW Values at 575V

kWAC 3-Phase per line, PF 0.85AC 1-Phase PF 0.85
0.5 kW0.5906 A1.02 A
0.75 kW0.886 A1.53 A
1 kW1.18 A2.05 A
1.5 kW1.77 A3.07 A
2 kW2.36 A4.09 A
2.5 kW2.95 A5.12 A
3 kW3.54 A6.14 A
3.5 kW4.13 A7.16 A
4 kW4.73 A8.18 A
5 kW5.91 A10.23 A
6 kW7.09 A12.28 A
7.5 kW8.86 A15.35 A
8 kW9.45 A16.37 A
10 kW11.81 A20.46 A
12 kW14.18 A24.55 A

Frequently Asked Questions

1.35 kW at 575V draws about 1.6 amps on an AC three-phase circuit at PF 0.85. Alternate cases at the same voltage: 2.35A on DC, 2.77A on AC single-phase.
DC: Amps = (kW × 1000) ÷ Volts. AC single-phase: Amps = (kW × 1000) ÷ (Volts × PF). AC three-phase: Amps = (kW × 1000) ÷ (VoltsL-L × √3 × PF).
1.35 kW can be either. Residential loads up to about 5 kW (water heaters, dryers, EV chargers at 240V) are usually single-phase; commercial panels often serve the same load three-phase at 208V or 480V.
Three-phase at 575V draws 1.6A per line versus 2.77A single-phase. Less current per conductor means smaller wire and lower I²R losses.
1.35 kW costs $0.23 per hour at $0.17/kWh (US residential average, last reviewed April 2026). At 8 hours/day that is $55.24 per month.
This calculator provides estimates for reference purposes only. Always consult a licensed electrician and verify compliance with the National Electrical Code (NEC) and local electrical codes before performing any electrical work.