How Many Amps Is 9.7 kW at 208V?

At 208V, 9.7 kW pulls approximately 31.66 amps on AC three-phase (PF 0.85). This is the case typical for commercial HVAC, industrial motors, rooftop units, and three-phase panel loads. Always verify against the equipment nameplate for actual install sizing.

9.7 kW at 208V, AC three-phase (PF 0.85)
31.66 Amps
9.7 kilowatts at 208V on AC three-phase ≈ 31.66 amps
AC Single Phase (PF 0.85)54.84 A
DC (ideal baseline)46.61 A
31.66

Formulas

DC: kW to Amps

I(A) = 1000 × P(kW) ÷ V(V)

1000 × 9.7 ÷ 208 = 9,695 ÷ 208 = 46.61 A

AC Single Phase (PF = 0.85)

I(A) = 1000 × P(kW) ÷ (PF × V(V))

9,695 ÷ (0.85 × 208) = 9,695 ÷ 176.8 = 54.84 A

AC Three Phase (PF = 0.85)

I(A) = 1000 × P(kW) ÷ (√3 × PF × VL-L), where VL-L is the line-to-line voltage

9,695 ÷ (1.732 × 0.85 × 208) = 9,695 ÷ 306.22 = 31.66 A

Equipment & Circuit Sizing

Breaker Sizing

Breaker ratings are in amps, not watts, so the real install answer depends on the equipment nameplate FLA, whether the load is continuous (NEC 210.19(A) sizes the conductor and OCP at 125% of a continuous load, equivalently 80% of breaker rating), conductor ampacity and temperature rating, ambient and bundling derates, and any motor or HVAC provisions (NEC 430 / 440). At roughly 31.66A on AC three-phase at 208V, the load sits in the bracket between a 35A standard size (non-continuous) and the next size up that covers a continuous load under 210.19(A) (around 40A). The actual install pick depends on whether the load is continuous and the factors above; a conversion page can't pick a single "right" breaker from the amp draw alone.

Energy Cost

9.7 kW costs $1.65/hour at $0.17/kWh (rates last reviewed April 2026). See breakdown.

Power Factor Reference (AC three-phase)

How the line current for 9.7 kW at 208V changes with load power factor, on the same AC three-phase circuit basis the rest of the page uses. DC has no power factor; PF 1.0 represents resistive AC loads.

Load TypePF9.7 kW at 208V (AC three-phase)
Resistive (heaters, incandescent)126.91 A
Fluorescent lamps0.9528.33 A
LED lighting0.929.9 A
Synchronous motors0.929.9 A
Typical mixed loads0.8531.66 A
Induction motors (full load)0.833.64 A
Computers (without PFC)0.6541.4 A
Induction motors (no load)0.3576.89 A

AC Conversion Comparison

On DC, 9.7kW at 208V draws 46.61A. AC single-phase at PF 0.85 pulls 54.84A because reactive current is added on top of the real power. Three-phase at the same voltage needs only 31.66A per line since the same 9.7kW is shared across three conductors instead of one.

Circuit TypeFormulaResult
DC9,695 ÷ 20846.61 A
AC Single Phase (PF 0.85)9,695 ÷ (0.85 × 208)54.84 A
AC Three Phase (PF 0.85)9,695 ÷ (1.732 × 0.85 × 208)31.66 A

Other kW Values at 208V

kWAC 3-Phase per line, PF 0.85AC 1-Phase PF 0.85
1 kW3.27 A5.66 A
1.5 kW4.9 A8.48 A
2 kW6.53 A11.31 A
2.5 kW8.16 A14.14 A
3 kW9.8 A16.97 A
3.5 kW11.43 A19.8 A
4 kW13.06 A22.62 A
5 kW16.33 A28.28 A
6 kW19.59 A33.94 A
7.5 kW24.49 A42.42 A
8 kW26.12 A45.25 A
10 kW32.66 A56.56 A
12 kW39.19 A67.87 A
15 kW48.98 A84.84 A
18 kW58.78 A101.81 A

Frequently Asked Questions

9.7 kW at 208V draws about 31.66 amps on an AC three-phase circuit at PF 0.85. Alternate cases at the same voltage: 46.61A on DC, 54.84A on AC single-phase.
9.7 kW costs $1.65 per hour at $0.17/kWh (US residential average, last reviewed April 2026). At 8 hours/day that is $395.56 per month.
9.7 kW equals 9,695 watts. Multiply kilowatts by 1000.
DC: Amps = (kW × 1000) ÷ Volts. AC single-phase: Amps = (kW × 1000) ÷ (Volts × PF). AC three-phase: Amps = (kW × 1000) ÷ (VoltsL-L × √3 × PF).
Three-phase at 208V draws 31.66A per line versus 54.84A single-phase. Less current per conductor means smaller wire and lower I²R losses.
This calculator provides estimates for reference purposes only. Always consult a licensed electrician and verify compliance with the National Electrical Code (NEC) and local electrical codes before performing any electrical work.