swap_horiz Looking to convert 62.5A at 24V back to watts?

How Many Amps Is 1,500 Watts at 24V?

1,500 watts equals 62.5 amps at 24V on a DC circuit. On AC single-phase at PF 0.85 the same real power would be 73.53 amps.

At 62.5A, the NEC 210.19(A) continuous-load sizing math (125% of the load, equivalently 80% of the breaker rating) points to a 80A breaker as the smallest standard size that covers this load continuously. A 70A breaker is the smallest standard size the raw current fits under, but it is non-continuous-only at this load.

1,500 watts at 24V
62.5 Amps
1,500 watts equals 62.5 amps at 24 volts (DC)
AC Single Phase (PF 0.85)73.53 A
62.5

Assumes a DC circuit. Typing a commercial L-L voltage (208/400/480V) re-routes the result to three-phase; 277V stays on single-phase because it's the L-N lighting leg of a 480Y/277V wye; 12/24V re-routes to DC.

Formulas

DC: Watts to Amps

I(A) = P(W) ÷ V(V)

1,500 ÷ 24 = 62.5 A

AC Single Phase (PF = 0.85)

I(A) = P(W) ÷ (PF × V(V))

1,500 ÷ (0.85 × 24) = 1,500 ÷ 20.4 = 73.53 A

Circuit Sizing

Breaker Sizing

NEC 240.6(A) standard ampere ratings for branch-circuit and feeder breakers start at 15, 20, 25, 30, 35, 40, 45, and 50A and continue at 60A and above for feeder and large-appliance circuits. At 62.5A, the smallest standard breaker the raw current fits under is 70A, but that breaker only covers 70A non-continuously; NEC 210.19(A) requires conductor and OCP sized at 125% of any continuous load (equivalently 80% of breaker rating), so for a continuous load the smallest compliant breaker is 80A. Final selection still depends on the equipment nameplate, whether the load is continuous, conductor ampacity, and local code.

Breaker SizeMax Continuous Load (80%)Status for 62.5A
45A36AToo small
50A40AToo small
60A48AToo small
70A56ANon-continuous only
80A64AOK for continuous
90A72AOK for continuous
100A80AOK for continuous
110A88AOK for continuous

Energy Cost

Running 1,500W costs approximately $0.26 per hour at the US average rate of $0.17/kWh (rates last reviewed April 2026). That is $2.04 for 8 hours or about $61.20 per month. See detailed cost breakdown.

AC Conversion Detail

The DC baseline for 1,500W at 24V is 62.5A. On an AC circuit with a power factor of 0.85, the current rises to 73.53A because reactive current flows alongside the real-power current.

Circuit TypeFormulaResult
DC1,500 ÷ 2462.5 A
AC Single Phase (PF 0.85)1,500 ÷ (24 × 0.85)73.53 A

Power Factor Reference

Power factor is the main reason 1,500W draws more current on AC than DC. At PF 1.0 (pure resistive, like a heater), the load pulls 62.5A at 24V on the single-phase basis the rest of the page uses. At PF 0.80 (typical induction motor), the same 1,500W pulls 78.12A. That is an extra 15.62A just to overcome the reactive component. Use the typical values below as a starting point, not for precise engineering calculations.

Load TypeTypical PF1,500W at 24V (single-phase)
Resistive (heaters, incandescent)162.5 A
Fluorescent lamps0.9565.79 A
LED lighting0.969.44 A
Synchronous motors0.969.44 A
Typical mixed loads0.8573.53 A
Induction motors (full load)0.878.12 A
Computers (without PFC)0.6596.15 A
Induction motors (no load)0.35178.57 A

Other Wattages at 24V

WattsDC AmpsAC 1Φ Amps PF 0.85
500W20.83A24.51A
600W25A29.41A
700W29.17A34.31A
750W31.25A36.76A
800W33.33A39.22A
900W37.5A44.12A
1,000W41.67A49.02A
1,100W45.83A53.92A
1,200W50A58.82A
1,300W54.17A63.73A
1,400W58.33A68.63A
1,500W62.5A73.53A
1,600W66.67A78.43A
1,700W70.83A83.33A
1,800W75A88.24A
1,900W79.17A93.14A
2,000W83.33A98.04A
2,200W91.67A107.84A
2,400W100A117.65A
2,500W104.17A122.55A

Frequently Asked Questions

1,500W at 24V draws 62.5 amps on DC. For comparison at the same voltage: 62.5A on DC, 73.53A on AC single-phase at PF 0.85. Actual current depends on the load's power factor.
Yes. Higher voltage means lower current for the same real power. 1,500W at 24V draws 62.5A on DC. As a resistive-baseline comparison at the same wattage, a DC or PF 1.0 load would draw 125A at 12V and 31.25A at 48V. Doubling the voltage halves the current and also halves the I²R losses in the conductors.
For resistive loads (heaters, incandescent bulbs, electric kettles) use PF 1.0. For motors, use 0.80. For mixed office/residential use 0.85. For computers and LED arrays the effective PF can be 0.65 or lower. Power factor only applies to AC.
AC circuits with reactive loads have a power factor below 1.0, so they draw extra current. At PF 0.85, 1,500W at 24V draws 73.53A instead of 62.5A (DC). That is about 18% more current for the same real power.
NEC 210.19(A) sizes the conductor and overcurrent device at not less than 125% of any continuous load (a load that runs three hours or more), equivalently 80% of the breaker rating. At 62.5A (the current the branch conductors actually carry on DC), the minimum breaker that satisfies this is 80A under typical assumptions. Brief non-continuous use can run closer to the full breaker rating, but space heaters, EV chargers, and long-running appliances should be sized for the continuous case.
This calculator provides estimates for reference purposes only. Always consult a licensed electrician and verify compliance with the National Electrical Code (NEC) and local electrical codes before performing any electrical work.