swap_horiz Looking to convert 8.35A at 240V back to watts?

How Many Amps Is 2,004 Watts at 240V?

2,004 watts equals 8.35 amps at 240V on an AC single-phase resistive circuit (PF 1.0). AC resistive at PF 1.0 and the DC baseline land on the same number at this voltage.

At 8.35A, the NEC 210.19(A) continuous-load sizing math (125% of the load, equivalently 80% of the breaker rating) points to a 15A breaker as the smallest standard size that covers this load continuously. At 240V, the lower current draw allows smaller wire and breakers compared to 120V.

2,004 watts at 240V

8.35 Amps

2,004 watts equals 8.35 amps at 240 volts (AC single-phase, PF 1.0 resistive)

DC8.35 A

Try: 2,000W at 240V 1,900W at 240V 2,200W at 240V 1,800W at 240V

Watts

Volts

Amps (AC 1Φ, PF 1.0)

8.35

Assumes an AC single-phase resistive load at PF 1.0. Typing a commercial L-L voltage (208/400/480V) re-routes the result to three-phase; 277V stays on single-phase because it's the L-N lighting leg of a 480Y/277V wye; 12/24V re-routes to DC.

Formulas

DC: Watts to Amps

I_(A) = P_(W) ÷ V_(V)

2,004 ÷ 240 = 8.35 A

AC Single Phase (PF = 0.85)

I_(A) = P_(W) ÷ (PF × V_(V))

2,004 ÷ (0.85 × 240) = 2,004 ÷ 204 = 9.82 A

Circuit Sizing

Breaker Sizing

NEC 240.6(A) standard ampere ratings for branch-circuit and feeder breakers start at 15, 20, 25, 30, 35, 40, 45, and 50A and continue at 60A and above for feeder and large-appliance circuits. At 8.35A, the smallest standard breaker the raw current fits under is 15A. NEC 210.19(A) sizes conductor and OCP at 125% of any continuous load, equivalently 80% of breaker rating. Final selection still depends on the equipment nameplate, whether the load is continuous, conductor ampacity, and local code.

Breaker Size	Max Continuous Load (80%)	Status for 8.35A
15A	12A	OK for continuous
20A	16A	OK for continuous
25A	20A	OK for continuous
30A	24A	OK for continuous
35A	28A	OK for continuous
40A	32A	OK for continuous
45A	36A	OK for continuous
50A	40A	OK for continuous

Energy Cost

Running 2,004W costs approximately $0.34 per hour at the US average rate of $0.17/kWh (rates last reviewed April 2026). That is $2.73 for 8 hours or about $81.76 per month. See detailed cost breakdown.

AC Conversion Detail

The DC baseline for 2,004W at 240V is 8.35A. On an AC circuit with a power factor of 0.85, the current rises to 9.82A because reactive current flows alongside the real-power current.

Circuit Type	Formula	Result
DC	2,004 ÷ 240	8.35 A
AC Single Phase (PF 0.85)	2,004 ÷ (240 × 0.85)	9.82 A

Power Factor Reference

Power factor is the main reason 2,004W draws more current on AC than DC. At PF 1.0 (pure resistive, like a heater), the load pulls 8.35A at 240V on the single-phase basis the rest of the page uses. At PF 0.80 (typical induction motor), the same 2,004W pulls 10.44A. That is an extra 2.09A just to overcome the reactive component. Use the typical values below as a starting point, not for precise engineering calculations.

Load Type	Typical PF	2,004W at 240V (single-phase)
Resistive (heaters, incandescent)	1	8.35 A
Fluorescent lamps	0.95	8.79 A
LED lighting	0.9	9.28 A
Synchronous motors	0.9	9.28 A
Typical mixed loads	0.85	9.82 A
Induction motors (full load)	0.8	10.44 A
Computers (without PFC)	0.65	12.85 A
Induction motors (no load)	0.35	23.86 A

Same Wattage, Other Voltages

bolt2,004W at 12V = 167ADC bolt2,004W at 24V = 83.5ADC bolt2,004W at 100V = 20.04A1Φ, PF 1.0 bolt2,004W at 120V = 16.7A1Φ, PF 1.0 bolt2,004W at 208V = 6.54A3Φ per line, PF 0.85 bolt2,004W at 220V = 9.11A1Φ, PF 1.0 bolt2,004W at 230V = 8.71A1Φ, PF 1.0 bolt2,004W at 277V = 7.23A1Φ, PF 1.0 bolt2,004W at 400V = 3.4A3Φ per line, PF 0.85 bolt2,004W at 460V = 2.96A3Φ per line, PF 0.85 bolt2,004W at 480V = 2.84A3Φ per line, PF 0.85 bolt2,004W at 575V = 2.37A3Φ per line, PF 0.85

swap_horiz 8.4A to watts at 240V payments 2,004W running cost cable Wire size for 8.35A at 240V electrical_services 2 kW to amps science Ohm's law: 240V & 8A functions Watts to amps formula

Other Wattages at 240V

Watts	AC 1Φ Amps PF 1.0 resistive	AC 1Φ Amps PF 0.85 motor
700W	2.92A	3.43A
750W	3.13A	3.68A
800W	3.33A	3.92A
900W	3.75A	4.41A
1,000W	4.17A	4.9A
1,100W	4.58A	5.39A
1,200W	5A	5.88A
1,300W	5.42A	6.37A
1,400W	5.83A	6.86A
1,500W	6.25A	7.35A
1,600W	6.67A	7.84A
1,700W	7.08A	8.33A
1,800W	7.5A	8.82A
1,900W	7.92A	9.31A
2,000W	8.33A	9.8A
2,200W	9.17A	10.78A
2,400W	10A	11.76A
2,500W	10.42A	12.25A
2,700W	11.25A	13.24A
3,000W	12.5A	14.71A

Frequently Asked Questions

How many amps is 2,004W at 240V? expand_more

2,004W at 240V draws 8.35 amps on AC single-phase at PF 1.0 (resistive). For comparison at the same voltage: 8.35A on DC, 9.82A on AC single-phase at PF 0.85. Actual current depends on the load's power factor.

What kind of 240V outlet does a 2,004W appliance need? expand_more

At US 240V a "regular outlet" is not a standard 120V NEMA 5-15R household receptacle, it's a dedicated 240V branch-circuit receptacle sized to the load. At 2,004W on 240V the current is 8.35A, which typically maps to a NEMA 6-15 receptacle on a 240V/15A circuit. Receptacle choice also depends on whether a neutral is needed, the equipment's cord and plug configuration, and any local amendments. Verify against the appliance's spec sheet and the receiving circuit.

What 240V circuit size does 2,004W need? expand_more

At 8.35A, this load sits well inside a 240V/15A dedicated branch circuit (NEMA 6-15) with headroom. Most installs that small are hard-wired rather than on a receptacle, but either works.

Why does AC draw more amps than DC for 2,004W? expand_more

AC circuits with reactive loads have a power factor below 1.0, so they draw extra current. At PF 0.85, 2,004W at 240V draws 9.82A instead of 8.35A (DC). That is about 18% more current for the same real power.

Does voltage affect how many amps 2,004W draws? expand_more

Yes. Higher voltage means lower current for the same real power. 2,004W at 240V draws 8.35A on AC single-phase at PF 1.0 (resistive). As a resistive-baseline comparison at the same wattage, a DC or PF 1.0 load would draw 16.7A at 120V and 4.18A at 480V. Doubling the voltage halves the current and also halves the I²R losses in the conductors.

This calculator provides estimates for reference purposes only. Always consult a licensed electrician and verify compliance with the National Electrical Code (NEC) and local electrical codes before performing any electrical work.