How Many Amps Is 16.8 kW at 400V?

At 400V, 16.8 kW pulls approximately 28.53 amps on AC three-phase (PF 0.85). This is the case typical for commercial HVAC, industrial motors, rooftop units, and three-phase panel loads. Always verify against the equipment nameplate for actual install sizing.

16.8 kW at 400V, AC three-phase (PF 0.85)
28.53 Amps
16.8 kilowatts at 400V on AC three-phase ≈ 28.53 amps
AC Single Phase (PF 0.85)49.41 A
DC (ideal baseline)42 A
28.53

Formulas

DC: kW to Amps

I(A) = 1000 × P(kW) ÷ V(V)

1000 × 16.8 ÷ 400 = 16,800 ÷ 400 = 42 A

AC Single Phase (PF = 0.85)

I(A) = 1000 × P(kW) ÷ (PF × V(V))

16,800 ÷ (0.85 × 400) = 16,800 ÷ 340 = 49.41 A

AC Three Phase (PF = 0.85)

I(A) = 1000 × P(kW) ÷ (√3 × PF × VL-L), where VL-L is the line-to-line voltage

16,800 ÷ (1.732 × 0.85 × 400) = 16,800 ÷ 588.88 = 28.53 A

Equipment & Circuit Sizing

Breaker Sizing

Breaker ratings are in amps, not watts, so the real install answer depends on the equipment nameplate FLA, whether the load is continuous (NEC 210.19(A) sizes the conductor and OCP at 125% of a continuous load, equivalently 80% of breaker rating), conductor ampacity and temperature rating, ambient and bundling derates, and any motor or HVAC provisions (NEC 430 / 440). At roughly 28.53A on AC three-phase at 400V, the load sits in the bracket between a 30A standard size (non-continuous) and the next size up that covers a continuous load under 210.19(A) (around 40A). The actual install pick depends on whether the load is continuous and the factors above; a conversion page can't pick a single "right" breaker from the amp draw alone.

Energy Cost

16.8 kW costs $2.86/hour at $0.17/kWh (rates last reviewed April 2026). See breakdown.

Power Factor Reference (AC three-phase)

How the line current for 16.8 kW at 400V changes with load power factor, on the same AC three-phase circuit basis the rest of the page uses. DC has no power factor; PF 1.0 represents resistive AC loads.

Load TypePF16.8 kW at 400V (AC three-phase)
Resistive (heaters, incandescent)124.25 A
Fluorescent lamps0.9525.52 A
LED lighting0.926.94 A
Synchronous motors0.926.94 A
Typical mixed loads0.8528.53 A
Induction motors (full load)0.830.31 A
Computers (without PFC)0.6537.31 A
Induction motors (no load)0.3569.28 A

AC Conversion Comparison

On DC, 16.8kW at 400V draws 42A. AC single-phase at PF 0.85 pulls 49.41A because reactive current is added on top of the real power. Three-phase at the same voltage needs only 28.53A per line since the same 16.8kW is shared across three conductors instead of one.

Circuit TypeFormulaResult
DC16,800 ÷ 40042 A
AC Single Phase (PF 0.85)16,800 ÷ (0.85 × 400)49.41 A
AC Three Phase (PF 0.85)16,800 ÷ (1.732 × 0.85 × 400)28.53 A

Other kW Values at 400V

kWAC 3-Phase per line, PF 0.85AC 1-Phase PF 0.85
3 kW5.09 A8.82 A
3.5 kW5.94 A10.29 A
4 kW6.79 A11.76 A
5 kW8.49 A14.71 A
6 kW10.19 A17.65 A
7.5 kW12.74 A22.06 A
8 kW13.58 A23.53 A
10 kW16.98 A29.41 A
12 kW20.38 A35.29 A
15 kW25.47 A44.12 A
18 kW30.57 A52.94 A
20 kW33.96 A58.82 A
22 kW37.36 A64.71 A
25 kW42.45 A73.53 A
30 kW50.94 A88.24 A

Frequently Asked Questions

16.8 kW at 400V draws about 28.53 amps on an AC three-phase circuit at PF 0.85. Alternate cases at the same voltage: 42A on DC, 49.41A on AC single-phase.
400V is commercial/industrial panel voltage, not a typical AC EVSE feed to a vehicle. On three-phase 400V, 16.8 kW works out to about 28.53A per line (three-phase at PF 0.85). In practice, 400-480V three-phase is usually the AC input to a DC fast charger (50-350 kW CCS/NACS stations like Tesla Superchargers), which rectifies to DC and delivers that directly to the vehicle, rather than an AC EVSE connector. A 16.8 kW figure at 400V is most likely the AC feed to a smaller commercial cabinet or the control-side input of a larger DC fast charger, not an at-the-car AC current.
Industrial equipment operates at higher power levels. 16.8 kW is easier to express than 16,800W. The math is identical, just scaled by 1000.
Three-phase at 400V draws 28.53A per line versus 49.41A single-phase. Less current per conductor means smaller wire and lower I²R losses.
16.8 kW equals 16,800 watts. Multiply kilowatts by 1000.
This calculator provides estimates for reference purposes only. Always consult a licensed electrician and verify compliance with the National Electrical Code (NEC) and local electrical codes before performing any electrical work.